This in turn will relate the weight of the block to the tensions in the other two ropes. The coordinate system shows horizontal to be along the x-axis and vertical to follow the y-axis.

Notice T and w are the only two forces acting on the block. is pulling the block up in the positive direction while the weight w pulls the block down in the negative direction.

The variables have been defined as: T rope and the block.

This system is useful because it relates the weight of the block to the tension in the rope.

Several familiar factors determine how effective you are in opening the door. First of all, the larger the force, the more effective it is in opening the door—obviously, the harder you push, the more rapidly the door opens. If you apply your force too close to the hinges, the door will open slowly, if at all.

Most people have been embarrassed by making this mistake and bumping up against a door when it did not open as quickly as expected.Example Problem: A block of weight w is suspended from a rope tied to two other ropes at point O. Assume the weights of the ropes and the knot are negligible.One rope is horizontally attached to a wall and the other is fastened to the ceiling. If the weight of the block is 100 N, what is the tension in the ceiling rope?This is because these are the only two forces actually connected to the block. Since the block is stationary (at equilibrium), the total of these two forces is equal to zero.ΣF = w Now we have the tension in the first of our ropes.Now, let’s find the tensions in the other two ropes.Note that r is the perpendicular distance of the pivot from the line of action of the force.(b) A smaller counterclockwise torque is produced by a smaller force F′ acting at the same distance from the hinges (the pivot point).Being careful with signs of forces and torques is important in writing the equations! Equilibrium is a special case in mechanics where all the forces acting on a body equal zero.Learn with extra-efficient algorithm, developed by our team, to save your time.The second condition necessary to achieve equilibrium involves avoiding accelerated rotation (maintaining a constant angular velocity.

## Comments Solving Equilibrium Problems Physics

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